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Hydraulic cylinder

Enter bore, rod, pressure and flow to see how much force the cylinder delivers, how long the stroke takes and whether the rod can carry the load without buckling.

Pre-sizing and estimating tool: results do not replace design, calculations or reports signed by a licensed professional, nor verification against the applicable codes and standards.

Pre-sizing
Cylinder
Power unit
Load and mounting
—Extend force
—

Force and speed extending, retracting and regenerative

Bars: force. Points: speed. Regenerative trades force for speed.

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Allowable buckling force versus stroke

Euler critical load divided by 3.5 for the chosen rod and mounting, compared with maximum extend force.

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Method, assumptions and references

Equations used

Forces: F_extend = p · A · ηm; F_retract = p · (A − Ar) · ηm; regenerative: F = p · Ar · ηm
Speeds: v = Q · ηv ÷ A (extend), ÷ (A − Ar) (retract), ÷ Ar (regenerative)
Buckling (Euler): Fk = π² · E · I ÷ Lk², I = π d⁴ ÷ 64, E = 210 GPa, Lk = (stroke + extra) × factor; F_allow = Fk ÷ 3.5

Assumptions and limits

  • Solid steel rod; back pressure on the opposite side neglected (except regenerative); seal friction included in mechanical efficiency.
  • Euler applies to slender rods; for short rods also use Tetmajer and material strength.

Standards and technical documents

  • ISO 3320: Fluid power — Cylinders — Bores and piston rod diameters
  • ISO 6020-1 e ISO 6022: cilindros hidráulicos de 160 e 250 bar
  • ISO 4413:2010: Hydraulic fluid power — General rules and safety requirements for systems and their components
  • Bosch Rexroth: The Hydraulic Trainer, vol. 1

U.S. regulations

  • OSHA 29 CFR 1910.217: mechanical power presses; 1910.147: control of hazardous energy
  • ANSI B11.2: hydraulic power presses

Frequently asked questions

How do I calculate hydraulic cylinder force?

Multiply pressure by piston area and mechanical efficiency. A 4 in bore at 2,500 psi pushes about 29,800 lbf at 95% efficiency.

Why is retraction faster?

On retraction, flow enters the annulus, which is smaller than the bore because the rod takes up part of it. The same flow in less area gives more speed and less force.

What is a regenerative circuit?

A connection where rod-side oil returns to the cap side during extension, increasing speed. Force drops to pressure × rod area.