Home / Utilities / Electrical installations

Machine energy use and cost calculator

List your machines, type your rate and see how many kWh and how much money each one uses per month, which weigh most on the bill and how much you can save.

Pre-sizing and estimating tool: results do not replace design, calculations or reports signed by a licensed professional, nor verification against the applicable codes and standards.

Preliminary estimateRevised 11/05/2026
Machines and equipment
See what was read

Nameplate power of one unit; quantity multiplies it. Load factor: how much of that power it uses, on average, while on (see the “?”). For motors in hp or shaft kW, the page divides by the efficiency below.

Energy rate
Output (optional)
Savings simulation

Your inputs stay only on this browser and are not sent anywhere. Untick to delete them.

—Energy cost per month
—

Who spends the most: monthly cost ranking

Monthly energy cost of each machine, from highest to lowest, with its share of the bill and the cumulative percentage.

Tap the chart to see the values.

How to read: each bar is one machine (or group); its length is the monthly cost. The label shows the amount, the share of the bill and, on wide screens, in brackets, the running total up to that bar (also in the table below). The top bars are the priorities: once the running total passes 80%, the rest of the list matters little.

Simulation: monthly cost before and after

Monthly cost of the chosen machine today, with fewer hours on, with a higher-efficiency motor, and with both measures.

Tap the chart to see the values.

How to read: the first bar is today’s cost; the others show the cost after each measure. The gap between the first and last bars is the total monthly saving. If the motor bar barely moves, a motor swap alone yields little: compare it with the new motor’s price before deciding.

Consumption and cost by machine

Key: avg kW = electrical power of one unit (nameplate ÷ efficiency, or V × I × PF) × quantity × load factor; kWh/month = avg kW × hours/day × days/month; cum. % = running total of the shares. The full table is in the .xlsx button at the end of the page.

Next step

Take this page’s results to another calculator with the fields already filled in.

The calculation report gathers this page's inputs, results, equations, assumptions and references, with fields for project, engineer and revision. The full report also includes the charts and interpretations, in color. In the print dialog, choose Save as PDF.

Method, assumptions and references

Equations used

Electrical power of one unit: kW = P (electrical kW); P_shaft ÷ η (motor; 1 hp = 0.7457 kW, 1 metric hp = 0.7355 kW); W ÷ 1000; V·I·PF ÷ 1000 (1-ph); √3·V·I·PF ÷ 1000 (3-ph)
Average power = kW × quantity × load factor; kWh/day = average power × hours/day; kWh/month = kWh/day × days/month; kWh/year = 12 × kWh/month
On-peak: kWh_peak = average power × min(hours/day; on-peak hours) × min(days/month; on-peak days), only for machines marked “on peak”; cost = kWh_peak × on-peak rate + (kWh − kWh_peak) × off-peak rate
Simulation: hours saving = average power × hours cut × days × the machine’s average rate; motor swap: saving = energy × (1 − η_current ÷ η_new)

Assumptions and limits

  • Estimate from the nameplate and usage data entered. The load factor is the average while on; the real result depends on it and should be checked with metering (power analyzer or utility interval data).
  • The rate is the one typed by the user; it excludes demand charges ($/kW) and power factor penalties.
  • A single efficiency for all motors; efficiency drops below 50% load. In the simulation, the motor swap applies only to machines in shaft kW, hp or metric hp, at the same shaft load.

Standards and technical documents

  • IEC 60034-30-1:2014 Rotating electrical machines — Efficiency classes of line operated AC motors (IE code)
  • IEC 60034-2-1:2014 Standard methods for determining losses and efficiency from tests
  • ISO 50001:2018 Energy management systems (energy review, significant energy uses)
  • ISO 50006:2014 Measuring energy performance using energy baselines and energy performance indicators
  • IEEE Std 1459-2010: Definitions for the Measurement of Electric Power Quantities

U.S. regulations

  • 10 CFR Part 431, Subpart B: energy conservation standards for electric motors (US DOE)
  • ISO 50001:2018 Energy management systems

Frequently asked questions

How do I calculate a machine’s energy use?

Multiply electrical power (kW) by the load factor and the hours it runs: kWh = kW × load × hours. For a motor, electrical power is the nameplate rating divided by efficiency. In the example, the 50 hp compressor draws 41.0 kW (50 × 0.7457 ÷ 0.91); at 75% load, 16 h a day and 22 days it uses 10,817 kWh per month, $1,190 at $0.11/kWh.

What is load factor and how do I estimate it?

It is how much of the nameplate power the machine uses, on average, while it is on. Motors seldom run full: machine tools sit at 30% to 50%, compressors at 60% to 80%, thermostat-controlled ovens at 50% to 80%. The safest way is to measure current with a clamp meter in normal operation and divide by nameplate current.

Which machines use the most energy in a plant?

Usually those combining high power and long hours: furnaces and ovens, air compressors, large pump and fan motors, and refrigeration. In the example, the hardening furnace ($2,677/month) and the compressor ($1,190/month) make up 66% of the $5,849 bill. The ranking shows where to act first.

How do on-peak and off-peak rates work?

Under time-of-use pricing, energy used during the utility’s on-peak window on weekdays costs more. Choose “On-peak and off-peak”, type both prices and mark which machines run in that window. The page shows how much of the bill comes from on-peak use and how much you save by moving load out of it.

How do I enter a machine by its current in amps?

Choose the unit “A 3-ph” or “A 1-ph” and type the measured or nameplate current. The page works out kW = √3 × V × I × PF ÷ 1000 for three-phase (or V × I × PF ÷ 1000 for single-phase), with the voltage and power factor from the fields just below the list. If current was measured in normal operation, use a 100% load factor.

How much do I save with a premium efficiency motor?

New energy is current energy × current efficiency ÷ new efficiency. Going from 91% to 94.5%, the saving is 1 − 91/94.5 = 3.7% of the motor’s energy. In the example, that is $44 per month on the compressor. Together with switching off 2 h a day, the saving reaches $187 per month. For payback, use the motor and VFD replacement calculator.

What are the limits of this calculator?

It is an estimate from nameplate and usage data. It excludes demand charges ($/kW) and power factor penalties. Motor efficiency is an average value. For investment decisions, confirm the consumption of the largest machines with metering.